Question

Assume Z is a standard normal random variable with mean 0 and variance 1.

Find P(Z<0.44)? Area below 0.44?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

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Assume Z is a standard normal random variable with mean 0 and variance 1.

Find P(Z>-1.76)? Area above -1.76?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

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Assume Z is a standard normal random variable with mean 0 and variance 1.

Find P(0.85<Z<1.36)?

Area between 0.85 and 1.36?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

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Assume Z is a standard normal random variable with mean 0 and variance 1.

Find the 10th percentile of Z?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, -3.5 is entered as -3.50, 0.3750 is entered as 0.38

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Assume Z is a standard normal random variable with mean 0 and variance 1.

Find z-score for which the area to its RIGHT is 0.39?

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

Answer 1

Assume Z is a standard normal random variable with mean 0 and variance 1.

Find P(Z<0.44)? Area below 0.44?

Answer: 0.67

Assume Z is a standard normal random variable with mean 0 and variance 1.

Find P(Z>-1.76)? Area above -1.76?

Answer: 0.96

Assume Z is a standard normal random variable with mean 0 and variance 1.

Find P(0.85<Z<1.36)?

Area between 0.85 and 1.36?

Answer : 0.11

Assume Z is a standard normal random variable with mean 0 and variance 1.

Find the 10th percentile of Z?

Answer: -1.28

Assume Z is a standard normal random variable with mean 0 and variance 1.

Find z-score for which the area to its RIGHT is 0.39?

Answer: 0.28