Question

Determine the margin of error for a confidence interval to estimate the population mean with nequals25 and s = 12.7 for the confidence levels below. a) 80% b) 90% c) 99% a) The margin of error for an 80% confidence interval is _.

Answer #1

Solution :

(a) At 80%

t_{
/2,df} = 1.318

Margin of error = E = t_{/2,df}
* (s /n)

= 1.318 * (12.7 / 25)

Margin of error = E = 3.35

(b)

At 90%

t_{
/2,df} = 1.711

Margin of error = E = t_{/2,df}
* (s /n)

= 1.711 * (12.7 / 25)

Margin of error = E = 4.35

(b)

At 99%

t_{
/2,df} = 2.797

Margin of error = E = t_{/2,df}
* (s /n)

= 2.797 * (12.7 / 25)

Margin of error = E = 7.10

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=
37
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a)
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a
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confidence interval when
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(Round to two decimal places as needed.)
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a
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(Round to two decimal places as needed.)
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