Question

State the mean and standard deviation of the sample proportion ˆp (sampling distribution).

State the mean and standard deviation of the sample proportion ˆp (sampling distribution).

Math   Statistics-And-Probability   
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Answer #1

Solution

mean of the sample proportion ˆp (sampling distribution).   = p =

standard deviation of the sample proportion ˆp (sampling distribution).   =  [p ( 1 - p ) / n] =   [(0.) / ] =

example

p = 0.1

1 - p = 1-0.1=0.9

n = 2

mean of the sample proportion ˆp (sampling distribution).

= p =0.1

standard deviation of the sample proportion ˆp (sampling distribution).

=  [p ( 1 - p ) / n] =   [(0.1*0.9) /2 ] = 0.212

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