Question

In a simple random sample if 25 law school graduates, you find the sample mean starting...

In a simple random sample if 25 law school graduates, you find the sample mean starting salary ̄X= $31,500 and the sample standard deviation s = $3000.Suppose further that the starting salary of law school graduates has a normal distribution. Carryout the following test of hypothesis at the level of significant α=.05.Determine the decision rule and your conclusion.Also, compute the observed level of significance for this test. H0:μ= 30,000 Ha:μ >30,000

Note: Please tell me which table you used when solve the problem.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1


0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1- It is believed that the mean μ starting salary for the new KU graduates has...
1- It is believed that the mean μ starting salary for the new KU graduates has increased from last year,s mean of $51 K annually. It is known that the standard deviation of the starting salary is σ = 5 K. To test what you believe, you collect a sample of 15 new graduates and find that the sample mean salary is x= 54 K. In this question and the next two, we will do a significance test to determine...
Suppose you want to test for whether there is a difference in starting salaries for those...
Suppose you want to test for whether there is a difference in starting salaries for those with a finance degree compared to those with an accounting degree. You sample 35 graduates with a finance degree and find the average starting salary to be 58,000 with a sample standard deviation of 5,000. You also take a sample of 40 graduates with an accounting degree and find the average starting salary 56,000 to be and a sample variance of 3000. Suppose you...
For a random sample of 17 recent business school graduates beginning their first job, the mean...
For a random sample of 17 recent business school graduates beginning their first job, the mean starting salary was found to be $43,500, and the sample standard deviation was $8,500. Assuming the population is normally distributed, calculate the lower confidence limit (LCL) of the population mean with α = 0.10.
A random sample of 115 observations produced a sample mean of 32. Find the critical and...
A random sample of 115 observations produced a sample mean of 32. Find the critical and observed values of z for the following test of hypothesis using α=0.025. The population standard deviation is known to be 6 and the population distribution is normal. H0: μ=28 versus H1: μ>28. Round your answers to two decimal places.
A random sample of 102 observations produced a sample mean of 30. Find the critical and...
A random sample of 102 observations produced a sample mean of 30. Find the critical and observed values of z for the following test of hypothesis using α=0.01. The population standard deviation is known to be 8 and the population distribution is normal. H0: μ=28 versus H1: μ≠28. Round your answers to two decimal places. zcritical left = zcritical right = zobserved =
A random sample of 101 observations produced a sample mean of 33. Find the critical and...
A random sample of 101 observations produced a sample mean of 33. Find the critical and observed values of z for the following test of hypothesis using α=0.02. The population standard deviation is known to be 6 and the population distribution is normal. H0: μ=28 versus H1: μ≠28. Round your answers to two decimal places. zcritical left = zcritical right = zobserved =
A sample of 37 observations is selected from a normal population. The sample mean is 25,...
A sample of 37 observations is selected from a normal population. The sample mean is 25, and the population standard deviation is 5. Conduct the following test of hypothesis using the .05 significance level. H0 : μ ≤ 24 H1 : μ > 24 (a) Is this a one- or two-tailed test? "One-tailed"-the alternate hypothesis is greater than direction. "Two-tailed"-the alternate hypothesis is different from direction. (b) What is the decision rule? (Round your answer to 2 decimal places.) H0,when...
A recent national survey found that high school students watched an average (mean) of 7.6 DVDs...
A recent national survey found that high school students watched an average (mean) of 7.6 DVDs per month with a population standard deviation of 0.5 hours. The distribution of times follows the normal distribution. A random sample of 61 college students revealed that the mean number of DVDs watched last month was 7.0. At the 0.01 significance level, can we conclude that college students watch fewer DVDs a month than high school students? Use α = 0.01. a. State the...
The average salary for American college graduates is $42,400. You suspect that the average is less...
The average salary for American college graduates is $42,400. You suspect that the average is less for graduates from your college. The 59 randomly selected graduates from your college had an average salary of $41,616 and a standard deviation of $8,550. What can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0:  ?...
Are you smarter than a second-grader? A random sample of 55 second-graders in a certain school...
Are you smarter than a second-grader? A random sample of 55 second-graders in a certain school district are given a standardized mathematics skills test. The sample mean score is x=55. Assume the standard deviation of test scores is σ=10. The nationwide average score on this test is 51. The school superintendent wants to know whether the second-graders in her school district have greater math skills than the nationwide average. Use the α=0.01 level of significance and the P-value method with...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT