The owner of anderson belts inc., is studing absenteeism among his employees. His workforce is ssmall, consisting of only 5 employees. For the last 3 years, 2014 through 2016, he recorded the following number of employee absences, in days, for each quarter.
Year | Q1 | Q2 | Q3 | Q4 |
2014 | 4 | 10 | 7 | 3 |
2015 | 5 | 12 | 9 | 4 |
2016 | 6 | 16 | 12 |
4 |
Answer info for
Quarter | Absenses | Moving Avg | Ratio to CMA | S/J | Seasonal Index | Desentasize |
Q12014 | 4 | 0.6900 | 5.7972 | |||
Q22014 | 10 | 1.6655 | 6.0042 | |||
Q32014 | 7 | 6.125 | 1.1429 | 1.1616 | 1.1685 | 5.9906 |
Q42014 | 3 | 6.5 | 0.4615 | 0.4732 | 0.4760 | 6.3024 |
Q12015 | 5 | 7 | 0.7143 | 0.6859 | 0.6900 | 7.2465 |
Q22015 | 12 | 7.375 | 1.6271 | 1.6557 | 1.6655 | 7.2050 |
Q32015 | 9 | 7.625 | 1.1803 | 3.9764 | 1.1685 | 7.7022 |
Q42015 | 4 | 8.25 | 0.4848 | 0.4760 | 8.4032 | |
Q12016 | 6 | 9.125 | 0.6575 | 0.6900 | 8.6958 | |
Q22016 | 16 | 9.5 | 1.6842 | 1.6655 | 9.6067 | |
Q32016 | 12 | 1.1685 | 10.2696 | |||
Q42016 | 4 | 0.4760 | 8.4032 |
The seasonal index is
Quarter | Seasonal Index |
1 | 0.6859 |
2 | 1.6557 |
3 | 1.1616 |
4 |
0.4732 |
Determine the linear trend equation based on the deseasonalized quarterly data for the three years. (round answer to 4 decimal places)
y = _____ + _____t
Solution:
We take x = 1, 2, ... and so on and y = Desentasize column
Using excel, <DATA < DATA ANALYSIS < REGRESSION
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.924502 | |||||
R Square | 0.854705 | |||||
Adjusted R Square | 0.840175 | |||||
Standard Error | 0.590411 | |||||
Observations | 12 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 20.50566 | 20.50566 | 58.82534 | 1.7E-05 | |
Residual | 10 | 3.485855 | 0.348585 | |||
Total | 11 | 23.99151 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 5.17415 | 0.363373 | 14.23922 | 5.76E-08 | 4.364504 | 5.983796 |
X Variable 1 | 0.378677 | 0.049373 | 7.669768 | 1.7E-05 | 0.268668 | 0.488686 |
The linear trend equation is
Y = 5.1742 + 0.3787t
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