hello, please write down each step on how you got the answers. thank you for your help.
Here we have given that 58% of adults plan to purchase a Fitbit next year(P).
Convert this percentage into decimal from ,P=0.58
Here we selected n=200 adults
We have to find probability of at least 120 out of 200 says "yes"
p=120/200=0.60
At least 120 out of 200 says yes of purchase FItbit next year is same as
Convert p in to z-score by using below formula
z=1.43
Use excel to find this probability
=NORMSDIST(1.43)
But this syntax give you P(z<1.43)=0.9236
Here we need P(Z>1.43)
Hence P(Z>1.43)=1-P(Z<1.43)
=0.0764
The probability that at least 120 of these adults will say “Yes” is 0.0764.
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