Use regression analysis to examine the variation in a dependent variable. Use 0.05 level of significance unless other stated.
Sunflower Clothing Chain
3. Sales for Sunflowers, a clothing chain, have increased during the past 12 years as the chain expanded the number of stores open. Until now, Sunflowers’ senior managers selected sites based on subjective factors. As the new director of planning, you will need to develop a systematic approach to selecting new sites. This plan must be able to forecast annual sales for all potential stores under consideration. You believe that the size of the store significantly contributes to the success of a store and want to use this relationship in the decision-making process.
Examine the relationship between the store size (thousands of square feet) and its annual sales (in million dollars) for Sunflowers women's clothing chain.
SUMMARY OUTPUT | |||||
Regression Statistics | |||||
Multiple R | 0.85 | ||||
R Square | 0.73 | ||||
Adjusted R Square | 0.71 | ||||
Standard Error | 1.69 | ||||
Observations | 14.00 | ||||
ANOVA | |||||
df | SS | MS | F | Significance F | |
Regression | 1 | 92.34 | 92.34 | 32.26 | 0.00 |
Residual | 12 | 34.34 | 2.86 | ||
Total | 13 | 126.68 | |||
Coefficients | Standard Error | t Stat | P-value | ||
Intercept | 1.02 | 0.92 | 1.11 | 0.29 | |
Square Feet (000) | 1.56 | 0.27 | 5.68 | 0.00 |
y = 1.02 + 1.56*x
For every square foot, sales will increase by 1.56.
The hypothesis being tested is:
H0: β1 = 0
H1: β1 ≠ 0
The p-value is 0.00.
Since the p-value (0.00) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that the slope is significant.
0.73 = 73% of the variation in the model is explained. This is a good fit.
Yes
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