Question

Refer to the general software output below in which x = NO₃⁻ wet deposition (g N/m²) and y = lichen N (% dry weight).

The regression equation is lichen N = 0.363 + 0.965 no3 depo
Predictor	Coef	Stdev	t-ratio	p
Constant	0.36304	0.09743	3.73	0.003
no3 depo	0.9646	0.1799	5.36	0.000
s = 0.1900   R-sq = 72.3%   R-sq (adj) = 69.8%

Is there evidence the explanatory variable is a significant predictor of the response? Use a significance level of 0.01.
State the appropriate null and alternative hypotheses.

H₀: β₁ = 0

H_a: β₁ ≠ 0

H₀: β₁ = 0

H_a: β₁ < 0    

H₀: β₁ = 0

H_a: β₁ > 0

H₀: β₁ ≠ 0

H_a: β₁ = 0
What is the t test statistic value? Round your answer to two decimal places.
t =  
What is the p-value? P-value =  
State the conclusion in the problem context.

Reject H₀. There is evidence the explanatory variable is a significant predictor of the response.

Reject H₀. There is no evidence the explanatory variable is a significant predictor of the response.    

Fail to reject H₀. There is evidence the explanatory variable is a significant predictor of the response.

Fail to reject H₀. There is no evidence the explanatory variable is a significant predictor of the response.

Answer 1