Before | After | di=xi-yi | di^2 | |
1 | 190 | 180 | 10 | 100 |
2 | 170 | 160 | 10 | 100 |
3 | 185 | 190 | -5 | fill in missing number |
4 | 160 | 160 | 0 | 0 |
5 | 200 | 190 | 10 | 100 |
Sum (Show excel formula) | ||||
Mean (Show excel formula) | ||||
Standard Deviation (Show excel formula) |
Complete the chart above and answer the questions below (show all work if using technology state the technology used and provide the formula)
1. What is the appropriate hypothesis test to use for this analysis: z-test for two proportions, t-test for two proportions, t-test for two dependent samples (matched pairs), or t-test for two independent samples?
2. Let μ1 = mean weight before the exercise regime. Let μ2 = mean weight after the exercise regime. Define the null hypothesis.
3. Let μ1 = mean weight before the exercise regime. Let μ2 = mean weight after the exercise regime. Defines the alternative hypothesis.
Formulas used:
SUM | =SUM(B3:B7) | =SUM(C3:C7) | =SUM(D3:D7) | =SUM(E3:E7) |
MEAN | =AVERAGE(B3:B7) | =AVERAGE(C3:C7) | =AVERAGE(D3:D7) | =AVERAGE(E3:E7) |
STANDARD DEVIATION | =STDEV.S(B3:B7) | =STDEV.S(C3:C7) | =STDDEV.S(D3:D7) | =STDDEV.S(E3:E7) |
Before | After | di=xi-yi | di^2 | |
1 | 190 | 180 | 10 | 100 |
2 | 170 | 160 | 10 | 100 |
3 | 185 | 190 | -5 | 25 |
4 | 160 | 160 | 0 | 0 |
5 | 200 | 190 | 10 | 100 |
Sum (Show excel formula) | 905 | 880 | 25 | 325 |
Mean (Show excel formula) | 181 | 176 | 5 | 65 |
Standard Deviation (Show excel formula) | 15.96871942 | 15.16575089 | 7.071067812 | 48.73397172 |
1. What is the appropriate hypothesis test to use for this analysis: z-test for two proportions, t-test for two proportions, t-test for two dependent samples (matched pairs), or t-test for two independent samples?
t-test for two dependent samples (matched pairs)
Solution2:
2. Let μ1 = mean weight before the exercise regime. Let μ2 = mean weight after the exercise regime. Define the null hypothesis.
H0:μ1 =μ2 that is μ1 -μ2=0 =====> μd =0
3. Let μ1 = mean weight before the exercise regime. Let μ2 = mean weight after the exercise regime. Defines the alternative hypothesis.
Alternative Hypothesis:
Ha: μ1 > μ2 that is μ1 -μ2>0 =====> μd>0
μd is difference in means before and after
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