Question

A bakery has five apple pies, three cherry pies and one rhubarb pie. The pies are not labeled and look identical. A pie is selected at random.

(a) What is the probability that it will be apple?

(b) What are the odds in favor of the selected pie being apple?

Answer 1

Total number of pies = 5A + 3C + 1R = 9

(a) Probability = Favorable outcomes / Total Outcomes

Favorable outcomes = choosing any one of the 5 apple pies

Total Outcomes = Choosing any one of the 9 apple pies.

Therefore the required probability = 5 / 9 = 0.5556

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(b) Odd in favor of an even = P(event will happen) : P(Even will not happen) = p : (1 - p)

Also P(Event will not happen) = 1 - P(Event will happen)

P(Apple pie is selected) = p = 5 / 9 (from a)

P(Apple pie is not selected) = 1 - 5 / 9 = 4 / 9

Therefore the odds in favor = 5/9 : 4/9 = 5 : 4

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