In an experiment, we are counting the number of customers who enter a bank in an hour. Suppose that the probability that no one enters the bank in an hour is 0.1. Determine the probability of entering 5 customers in two hours.
let expected number of customer in 1 hour=
hence no customer in 1 hour =P(X=0)=e-*0/0! =e- =0.1
hence =-ln(0.1)=2.3026
hence expected number of customer in 2 hour =2*2.3026=4.605
hence probability of entering 5 customers in two hours =P(X=5)=e-4.605*4.6055/5! =0.1726
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