Question

Seattle recently passed a tax no sugary drinks. You are interested in the proportion of students...

Seattle recently passed a tax no sugary drinks. You are interested in the proportion of students who support this tax. You collect a random sample and survey each member by asking "Do you support the sugar-tax?" You record your data as "1" for yes answer, and "0" for any other answer. Below is your sample data:

{1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 1, 0, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 0, 1, 0, 0, 1, 1, 1, 0, 0, 1}

1. What is the population you want to study?

2. Check the 4 condition that required to construct a confidence interval.

3. Construct a 95% confidence interval for the proportion of your population that supports the sugary drink tax.

4. Interpret your interval.

5. Approximately how many students would you have yo survey if you wanted a margin of error of 0.06?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
According to medical studies, the world’s intake of sugary drinks has led to an increase in...
According to medical studies, the world’s intake of sugary drinks has led to an increase in health issues, including heart disease and diabetes. This has led to negative externalities for the world’s population. Countries, including Great Britain and Finland, are dealing with the externality by establishing a sugar tax. In your opinion, do sugar drinks cause negative externalities? What is a negative externality? Ad do you believe the tax would correct it? Your answer must be a minimum of 5...
A soft drink manufacturer wishes to know how many soft drinks teenagers drink each week. They...
A soft drink manufacturer wishes to know how many soft drinks teenagers drink each week. They want to construct a 99% confidence interval with an error of no more than 0.06. A consultant has informed them that a previous study found the mean to be 3.7 soft drinks per week and found the standard deviation to be 1. What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next integer.
­­­­­­­­­­­­­­­­Q-10 (1 of 1) A soft drink manufacturer wishes to know how many soft drinks adults...
­­­­­­­­­­­­­­­­Q-10 (1 of 1) A soft drink manufacturer wishes to know how many soft drinks adults drink each week. They want to construct a 95% confidence interval for the mean and are assuming that the population standard deviation for the number of soft drinks consumed each week is 1.1. The study found that for a sample of 949 adults the mean number of soft drinks consumed per week is 3.6 Construct the desired confidence interval. Round your answers to one...
Suppose you want to estimate the proportion of all OSU students who use the app TikTok....
Suppose you want to estimate the proportion of all OSU students who use the app TikTok. You survey a random sample of 225 OSU students and 46 of these students indicate they use TikTok. B. Use your sample proportion to construct a 95% confidence interval. As you are calculating the margin of error, round your work to three decimal places in order to be as precise as possible, and show all of your work! In the spaces below, write down...
A survey is sent to 45 UCF students asking whether or not they understand UCF's "excess...
A survey is sent to 45 UCF students asking whether or not they understand UCF's "excess credit hours" policy. Of those, 36 students answered that they did. Construct the 95% confidence interval for to try to cover the population proportion of UCF students who understand that policy. Answer the following questions related to that confidence interval, rounding all numeric responses to the nearest hundredths. What is the point estimate sample proportion?   What is the standard error?   What is the lower...
1. A university Dean is interested in determining the proportion of students who receive some sort...
1. A university Dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than examine the records for all students, the dean randomly selects 200 students and finds that 118 of them are receiving financial aid. By hand, and using formulas for the “Margin of Error” (i.e. not calculator confidence interval), find a 98% confidence interval to estimate the true proportion of students on financial aid. (Use 3 decimal places for proportions.) 2....
Nearly all of Seattle’s soda tax is being passed on to consumers, new report shows Stores...
Nearly all of Seattle’s soda tax is being passed on to consumers, new report shows Stores across the city have passed on the cost of Seattle’s soda tax to consumers, a new study shows. (Ken Lambert / The Seattle Times) The city collected nearly $17 million in the first nine months of the tax — and officials are counting on the money to keep rolling in. By Daniel Beekman Seattle Times staff reporter Nearly 100 percent of Seattle’s new tax...
1. Suppose a survey is conducted using a random sample to determine whether voters in a...
1. Suppose a survey is conducted using a random sample to determine whether voters in a city are in favour of some project. A sample with n =100 observations is obtained, and the proportion found to be in favour of the motion is 40% i) Construct a 95% confidence interval for the proportion among the entire population that supports the project. ii) Construct a 99% confidence interval for the proportion among the entire population that supports the project. iii) What...
Suppose you wish to determine the true proportion of the population that supports marijuana legalization. You...
Suppose you wish to determine the true proportion of the population that supports marijuana legalization. You poll a randomly selected sample of 400 individuals and find 61% of them support legalization. (a) What is your point estimate for the proportion? (b) Show that the success/failure conditions hold. (c) Find the standard error for this estimate. (d) Compute a 95% confidence interval for this estimate. (e) Compute a 99% confidence interval for this estimate.
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 78. Which of the following is a correct interpretation of the interval 0.13 < p < 0.27? Check all that are correct. 0 There is a 90% chance that the proportion of the population is between 0.13 and 0.27. 0 The proprtion of all students who take notes is between 0.13 and...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT