Student |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
Movies |
12 |
2 |
13 |
17 |
14 |
9 |
24 |
6 |
26 |
22 |
10 |
16 |
Sports |
7 |
4 |
13 |
4 |
9 |
15 |
18 |
4 |
11 |
9 |
5 |
2 |
Difference (movies – sports) |
The hypothesis being tested is:
H0: µd = 0
Ha: µd ≠ 0
Movies | Sports | Difference |
12 | 7 | 5 |
2 | 4 | -2 |
13 | 13 | 0 |
17 | 4 | 13 |
14 | 9 | 5 |
9 | 15 | -6 |
24 | 18 | 6 |
6 | 4 | 2 |
26 | 11 | 15 |
22 | 9 | 13 |
10 | 5 | 5 |
16 | 2 | 14 |
14.250 | mean Movies | |
8.417 | mean Sports | |
5.833 | mean difference (Movies - Sports) | |
6.780 | std. dev. | |
1.957 | std. error | |
12 | n | |
11 | df | |
2.980 | t | |
.0125 | p-value (two-tailed) |
The p-value is 0.0125.
Since the p-value (0.0125) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that there is a difference in mean attendance between these two social activities for these students.
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