Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 90% confidence that the sample mean is plus or minus5 IQ points of the true mean. Assume that the standard deviation is 17 and determine the required sample size.
Solution :
Given that,
standard deviation = =17
Margin of error = E = 5
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645 ( Using z table ( see the 0.05 value in
standard normal (z) table corresponding z value is 1.645
)
sample size = n = [Z/2* / E] 2
n = ( 1.645 * 17 /5 )2
n =31.2816(rounded)
Sample size = n =31
Get Answers For Free
Most questions answered within 1 hours.