Question

1. Listed below are the amounts of mercury (in parts per million, or ppm) found in tuna sushi sampled at different stores. The sample mean is 1.211 ppm and the sample standard deviation is 0.257 ppm. Use technology to construct a 90% confidence interval estimate of the mean amount of mercury in the population. Assume a normal population.
   1.43   1.11   1.42   0.95   1.45   0.81   1.31

Answer 1

Solution:-

Data
Mean	1.211429
Standard Error	0.097307
Median	1.31
Mode	-
Standard Deviation	0.257451
Sample Variance	0.066281
Kurtosis	-1.33654
Skewness	-0.67751
Range	0.64
Minimum	0.81
Maximum	1.45
Sum	8.48
Count	7

90% confidence interval estimate of the mean amount of mercury in the population is C.I = ( 1.045, 1.397).

C.I = 1.211 + 1.813 × 0.09714

C.I = 1.2211 + 0.17611

C.I = ( 1.045, 1.397)