In 1993, 6.1% of people used cocaine.
This year, a company wishes to use their employment drug screening to test a claim. They take a simple random sample of 1824 job applicants and find that 100 individuals fail the drug test for cocaine. They want to test the claim that the proportion of the population failing the test is lower than 6.1%. Use .005 for the significance level. Round to three decimal places where appropriate.
Hypotheses:
Ho:p=6.1%
H1:p<6.1%
Test Statistic: z =
Critical Value: z =
p-value:
Conclusion About the Null:
Conclusion About the Claim:
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