A young investor believes that he can beat the market by picking stocks that will increase in value. Assume that on average 47 % of the stocks selected by a portfolio manager will increase over 12 months. Of the 28 stocks that the young investor bought over the last 12 months, 19 have increased. Can he claim that he is better at predicting increases than the typical portfolio manager? Test at alphaequals0.05. What are the null and alternative hypotheses for this test? A. H0: pequals0.47 vs. HA: pless than0.47 B. H0: pequals0.47 vs. HA: pgreater than0.47 C. H0: pequals0.47 vs. HA: pnot equals0.47 D. H0: pnot equals0.47 vs. HA: pequals0.47 Calculate the test statistic. A. The test statistic is nothing. (Round to two decimal places as needed.) B. The test statistic cannot be calculated. The conditions for a hypothesis test are not all met. What is the P-value for the test statistic? A. The P-value is nothing. (Round to three decimal places as needed.) B. The P-value cannot be calculated. The conditions for a hypothesis test are not all met. What can the investor conclude? Assume alphaequals0.05. A. He rejects the null hypothesis and cannot claim that he is better at predicting increases than the typical portfolio manager, but this conclusion may not be reliable. B. He rejects the null hypothesis and can claim that he is better at predicting increases than the typical portfolio manager, but this conclusion may not be reliable. C. He fails to reject the null hypothesis and can claim that he is better at predicting increases than the typical portfolio manager, but this conclusion may not be reliable. D. He fails to reject the null hypothesis and cannot claim that he is better at predicting increases than the typical portfolio manager, but this conclusion may not be reliable. E. No conclusion can be made. The conditions for a hypothesis test are not all met.
null Hypothesis: Ho: p | = | 0.470 | |
alternate Hypothesis: Ha: p | > | 0.470 |
sample success x = | 19 | |
sample size n = | 28 | |
std error se =√(p*(1-p)/n) = | 0.0943 | |
sample proportion p̂ = x/n= | 0.6786 | |
test stat z =(p̂-p)/√(p(1-p)/n)= | 2.21 |
p value = | 0.014 |
B. He rejects the null hypothesis and can claim that he is better at predicting increases than the typical portfolio manager, but this conclusion may not be reliable.
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