Question

(Q24-Q27) An insurance company has gathered the information regarding the number of accidents reported per day over a period of 100 days. The data can be found on the fourth sheet labeled “Accidents” in the “INFO1020 Final Exam DataFile.xlsx”. With the data, you are conducting a goodness-of-fit test to see whether the number of accidents per day can have a Poisson distribution. 24.What is the expected frequency of exactly 2 accidents per day? 25.What is the Chi-square test statistics? Round the value to 4 decimal places, e.g., round 0.25645 up to 0.2565, and round 0.25643 down to 0.2564. 26.What is the p-value? 27.At the 10% level of significance, what is the conclusion of this test? Data: Accidents per day 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5

Answer 1

p	x	Oi	Ei	(Oi - Ei)^2/Ei
0.074273578	0	5	7.427358	0.79329233
0.193111303	1	18	19.31113	0.089019272
0.251044694	2	25	25.10447	0.000434738
0.217572068	3	24	21.75721	0.231193332
0.141421844	4	20	14.14218	2.426358046
0.122576511	5	8	12.25765	1.47887983
0.877423489		100	100	5.019177547
		260
lambda	2.6		p-value	0.413544221

lambda = 2.6

24).What is the expected frequency of exactly 2 accidents per day = 25.10447

25)TS = 5.0192

26)p-value = 0.4135

27)

we fail to reject the null hypothesis as p-value > 0.10

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