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In a health examination survey of a province in Canada, the population was found to have...

In a health examination survey of a province in Canada, the population was found to have an average fasting blood glucose level of µ = 99.0 with a standard deviation of σ = 12. Assume the fasting blood glucose level for the population is normally distributed. Randomly select a person in that province and let X be the fasting blood glucose level of the person selected.

(a) Find P(90 < X < 110).

(b) Find x-value so that P(X < x) = 0.90, that is the 90th percentile of the population.

(c) A sample size of 4 was taken and let X¯ denotes the sample mean. Find P(90 < X <¯ 110)

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