Question

In a health examination survey of a province in Canada, the population was found to have...

In a health examination survey of a province in Canada, the population was found to have an average fasting blood glucose level of µ = 99.0 with a standard deviation of σ = 12. Assume the fasting blood glucose level for the population is normally distributed. Randomly select a person in that province and let X be the fasting blood glucose level of the person selected.

(a) Find P(90 < X < 110).

(b) Find x-value so that P(X < x) = 0.90, that is the 90th percentile of the population.

(c) A sample size of 4 was taken and let X¯ denotes the sample mean. Find P(90 < X <¯ 110)

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose we know that examination scores have a population standard deviation of σ = 25. A...
Suppose we know that examination scores have a population standard deviation of σ = 25. A random sample of n = 400 students is taken and the average examination score in that sample is 75. Find a 95% and 99% confidence interval estimate of the population mean µ.
a. Nonpregnant women have an average fasting blood glucose level of about 80 mg/100mL of blood....
a. Nonpregnant women have an average fasting blood glucose level of about 80 mg/100mL of blood. Researchers want to determine if pregnancy causes a change in blood glucose level. They take a random sample of 25 third trimester women and find their average fasting blood glucose level is 75 mg/100mL with sample standard deviation of 9.68. Find 90% and 95% confidence intervals for average fasting blood glucose level of third trimester women. b. Repeat the previous question, but this time...
Question #8: The score of the LSAT examination have a population mean µ = 70 and...
Question #8: The score of the LSAT examination have a population mean µ = 70 and population standard deviation σ = 10. Answer the questions below and show work. 1.) A random sample of 64 individuals is taken. What is the probability that the sample mean is below 71? 2.) A random sample of 100 individuals is taken. What is the probability that the sample mean is below 71?
4) The National Health and Nutrition Examination survey estimated dietary intake of ten key nutrients. One...
4) The National Health and Nutrition Examination survey estimated dietary intake of ten key nutrients. One of those nutrients was calcium (mg). They found in all adults 60 years or older a mean calcium intake of 721 mg with a standard deviation 454 mg. Assume that these values are for the population mean and standard deviation for the US population. Also, assume that the calcium intake measurements of this random variable have a population distribution shape that is skewed to...
A survey described the results of a poll of working adults in Canada. Each person in...
A survey described the results of a poll of working adults in Canada. Each person in a random sample was classified according to gender and the number of vacation days he or she usually took each year. The resulting data are summarized in the given table. Days of Vacation Gender Male Female None 51 42 1-5 21 25 6-10 67 79 11-15 105 94 16-20 71 70 21-25 82 58 More than 25 118 79 (a) Is it reasonable to...
A person's blood glucose level and diabetes are closely related. Let x be a random variable...
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. Suppose that after a 12-hour fast, the random variable x will have a distribution that is approximately normal with mean μ = 90 and standard deviation σ = 21. Note: After 50 years of age, both the mean and standard deviation tend to increase. For an adult (under 50) after a...
please answer all the questions 1. A Confidence Interval (CI) for a population characteristic is: An...
please answer all the questions 1. A Confidence Interval (CI) for a population characteristic is: An alternative to a Point Estimate An interval of plausible values for a population characteristic An interval of ranges for a large sample that is unbiased A population of critical values Directions: Find each specified point estimate or confidence interval. 2. A survey of teachers reports that a point estimate for the mean amount of money spent each week on lunch is $18.00. If the...
1.Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks,...
1.Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose readings from this horse (in mg/100 ml). 93 89 80 103 98 109 84 91 The sample mean is x ≈ 93.4. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that σ = 12.5. The mean glucose level...
A. 94 89 80 105 99 112 83 87 The sample mean is x ≈ 93.6....
A. 94 89 80 105 99 112 83 87 The sample mean is x ≈ 93.6. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that σ = 12.5. The mean glucose level for horses should be μ = 85 mg/100 ml.† Do these data indicate that Gentle Ben has an overall average glucose level higher than 85? Use α =...
Let X1, X2 be two normal random variables each with population mean µ and population variance...
Let X1, X2 be two normal random variables each with population mean µ and population variance σ2. Let σ12 denote the covariance between X1 and X2 and let ¯ X denote the sample mean of X1 and X2. (a) List the condition that needs to be satisfied in order for ¯ X to be an unbiased estimate of µ. (b) [3] As carefully as you can, without skipping steps, show that both X1 and ¯ X are unbiased estimators of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT