Question

Color blindness in humans is recessive. A heterozygous man and a woman who is homozygous for...

Color blindness in humans is recessive. A heterozygous man and a woman who is homozygous for color blindness decide to raise a family of 3 children.

a) What is the probability that 2 of the children have normal vision, and 1 are color blind?

b) What is the probability that 1 of the children has normal vision, and 2 are color blind?

c) What is the probability that all of the children are color blind?

d) What is the probability that all of the children have normal vision?

Math   Statistics-And-Probability   
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Answer #1

here probability of a child being color blind depends on if child gets color blindness responsible trait from father which is 1/2

a)

probability that 2 of the children have normal vision, and 1 are color blind =3C2(1/2)1(1/2)2=3/8

b)

probability that 1 of the children has normal vision, and 2 are color blind =3C2(1/2)2(1/2)1=3/8

c) probability that all of the children are color blind =3C3(1/2)3(1/2)0=1/8

d)

probability that all of the children have normal vision =3C0(1/2)0(1/2)3=1/8

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