19A telecommunications company wants to estimate the proportion of households that would purchase an additional telephone line if it were made available at a substantially reduced installation cost. Data are collected from a random sample of 500 households. The results indicate that 145 of the households would purchase the additional telephone line at a reduced installation cost. Complete parts (a) and (b) below. a. Construct a 99% confidence interval estimate for the population proportion of households that would purchase the additional telephone line.
Solution :
Given that,
Point estimate = sample proportion = = x / n = 145 / 500 = 0.290
1 - = 1 - 0.290 = 0.71
Z/2 = 2.576
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 * (((0.290 * 0.71) / 500)
= 0.052
A 99% confidence interval for population proportion p is ,
- E < p < + E
0.290 - 0.052 < p < 0.290 + 0.052
0.238 < p < 0.342
The 99% confidence interval for the population proportion p is : 0.238 , 0.342
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