Suppose you are told that a 95% confidence interval for the average price of a gallon of regular gasoline in your state is from $3.23 to $4.20. Use the fact that the confidence interval for the mean is in the form x − Eto x + E to compute the sample mean and the maximal margin of error E. (Round your answers to two decimal places.)
x = $ | |
E = $ |
Let
L = lower bound of confidence interval
U = upper bound of confidence interval
We're given that L = 3.23 and U = 3.45
So
L = X - E
3.23 = X - E
and
U = X + E
3.45 = X + E
The equations are
3.23 = X - E
3.45 = X + E
Add them up to get
6.68 = 2X + 0E
6.68 = 2X
2X = 6.68
X = 6.68/2
X = 3.34
The sample mean is xbar = 3.34
3.23 = X - E
3.23 = 3.34 - E
3.23 - 3.34 = -E
-0.11 = -E
-E = -0.11
E = 0.11
The margin of error is 0.11
So the sample mean is $3.34 and the margin of error is $0.11 (11 cents)
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