Question

# In a certain town, 39.1% of the voters are Democrats and 60.9% of the voters are...

In a certain town, 39.1% of the voters are Democrats and 60.9% of the voters are Republicans. In the last election 30.8% of the Democrats, and 39.6% of the Republicans voted.

a) If a citizen who voted in the last election is randomly selected, what is the probability that they are a Republican?

b) If a citizen who is a Democrat is randomly selected, what is the probability that they did not vote in the last election?

*please answer both parts and explain and pay attention to republican and democrat the last two people who answered did not answer question correctly part a is for republicans and part b refrences democrats that did not vote

 Democrats voters 39.1% Republicans voters 60.9% Democrats voted 30.8% Republicans voted 39.6%

a.

If a citizen who voted in the last election is randomly selected, what is the probability that they are a Republican?

39.6% - 30.8% = 8.8%

probability that they are a Republican = 0.088

b.

If a citizen who is a Democrat is randomly selected, what is the probability that they did not vote in the last election?

39.1% + 30.8% = 69.9%

probability that Democrat did not vote in the last election = 0.699

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