Question

Consider the experimental results for the following randomized block design. Make the calculations necessary to set up the analysis of variance table.

		Treatment
		A		B		C
	1	10		10		9
	2	13		6		6
Blocks	3	18		16		15
	4	21		18		19
	5	8		8		9

Use = .05 to test for any significant differences. Show entries to 2 decimals, if necessary. If your answer is zero enter "0".

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F
Treatments
Blocks
Error
Total

The p-value is Selectless than .01between .01 and .025between .025 and .05between .05 and .10greater than .10

What is your conclusion?

Answer 1

using excel data analysis tool for two factor anova, following o/p Is obtained : write data>menu>data>data analysis>anova :two factor without replication>enter required labels>ok, and following o/p Is obtained,

Anova: Two-Factor Without Replication
SUMMARY	Count	Sum	Average	Variance
1	3	29	10	0.333
2	3	25	8	16.333
3	3	49	16	2.333
4	3	58	19	2.333
	3	25	8	0.333
A	5	70	14	29.500
B	5	58	142	26.800
C	5	58	134	27.800
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
treatment	19.20	2	9.60	3.18	0.0962	4.46
block	312.27	4	78.07	25.88	0.0001	3.84
Error	24.13	8	3.02
Total	355.60	14

0.05<p value<0.10

  

there is no significant difference