Question

Political theorists have suggested that one-third (33.3%) of people will always support and one-third will always oppose any proposition. Out of a random sample of 90 recently surveyed registered voters in California , 36 opposed Proposition 1A. Does this proposition have more than the expected amount of opposition? Use alpha=.05

What is the null hypothesis?

1. ☐ H_o: π = .40
2. ☐ H_0: π = 0
3. _☐H_0: π = .33
4. ☐H_0: π > .40
5. ☐H_0: π > .33

What is the alternative hypothesis?

1. ☐ H_A: π >.33
2. ☐H_A: π =.40
3. ☐H_A: π >.40
4. ☐H_A: π < .33
5. ☐H_A: π >0

What is your critical value separating the regions of rejection and non-rejection?

When you turn your sample proportion into a Z score, what is that Z score?

What is your decision? Reject? ☐ Not reject?☐

What does your decision mean?

1. ☐ The H₀ is true and the proportion is .333 or 333%
2. ☐ The H₀ may be true; I cannot prove that the proportion is greater than .333
3. ☐ The H₀ is false: I cannot prove that the proportion is greater than .333
4. ☐The H₀ is false: The proportion is greater than .333
5. ☐The H₀ is true: The proportion is less than .333

What is the exact p value for your statistic above (use the Z table)?

Relative to the alpha values listed in the t table, what is the relative p value of your finding? p<

Answer 1

Null hypothesis, H0: π = .33

Alternative hypothesis, HA: π >.33 (since Claim: this proposition have more than the expected amount of opposition)

critical value=z0.05=1.64

Since Z-score<1.64 so Not reject H0.

Decision: The H0 may be true; I cannot prove that the proportion is greater than .333.