A teacher is interested in the relationship between the time spent studying for an exam and exam score. The table lists scores for 5 students. The value of b0 = 67.91 and the value of b1 = 0.75 Hours studied 5 18 3 15 17 Exam score 63 87 79 72 82 . Step 5 of 6 : Calculate the variance of the error (s2e). Round intermediate values and final answer to two decimal places.
the regression equation is:-
exam score= 67.91 + 0.75 hours
table for necessary calculation:-
hours | exam score(y) | predicted exam score() | residual 2=(y - )2 |
5 | 63 | 67.91+(5*0.75) = 71.66 | (63-71.66)^2 = 74.00 |
18 | 87 | 81.41 | 31.25 |
3 | 79 | 70.16 | 78.15 |
15 | 72 | 79.16 | 51.27 |
17 | 82 | 80.66 | 1.80 |
total | ------- | ------ | 236.47 |
so,error variance:-
hence the variance of error = 59.12
***If you have any doubt regarding the problem please write it in the comment section.if you are satisfied please give me a LIKE if possible...
Get Answers For Free
Most questions answered within 1 hours.