The relative frequency of people who prefer cigarette is:
[A] 0.2 [B] 40 [C] 7 [D] 0.035
[A] -0.3 [B] 4.6 [C] 4.9 [D] -2.6
[A] approx. 5% [B] at least 75% [C] at most 25% [D] approx. 95%
1)
data is not given
2)
mean = 2.3 , s = 1.3
z value = -2
z = (x - mena)/sigma
-2 = (x - 2.3)/1.3
x = -2*1.3+ 2.3
x= -0.3
3)
Here, μ = 78, σ = 6, x1 = 66 and x2 = 90. We need to compute P(66<= X <= 90). The corresponding z-value is calculated using Central Limit Theorem
z = (x - μ)/σ
z1 = (66 - 78)/6 = -2
z2 = (90 - 78)/6 = 2
Therefore, we get
P(66 <= X <= 90) = P((90 - 78)/6) <= z <= (90 -
78)/6)
= P(-2 <= z <= 2) = P(z <= 2) - P(z <= -2)
= 0.9772 - 0.0228
= 0.9544
approx. 95%
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