Attached below is the 2-way frequency table for patient group and gender, also called the joint frequency table. Use this data to answer question 1.
Patients |
Female |
Male |
Trauma Patient |
2 |
6 |
Volunteer |
39 |
48 |
a. Let T = Event that the subject is a trauma patient
and M = Event that the subject is a male
Probability that the patient selected is a trauma patient and is a male
= P(TM)
= No. of patients who are trauma patients and are males / Total no. of subjects
= 6 / 95
= 0.0632
Probability that the patient selected is a trauma patient and is a male is 0.0632
b. Let V = Selected subject is a volunteer
F = Event that the selected subject is female
Probability that they are a volunteer GIVEN they are female
= P ( V | F)
= P(VF) / P(F)..................(Property of conditional probability)
From the 2x2 table,
= (39/95) / (41/95)
= (39/41)
= 0.9512
Probability that the patient selected is a volunteer GIVEN that the patient is a female is 0.9512.
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