One particular morning, the length of time spent in the
examination rooms is recorded for each patient seen by each
physician at an orthopedic clinic.
Time in Examination Rooms (minutes) | |||
Physician 1 | Physician 2 | Physician 3 | Physician 4 |
34 | 32 | 19 | 26 |
22 | 34 | 32 | 35 |
25 | 32 | 32 | 32 |
32 | 28 | 25 | 29 |
24 | 40 | 34 | 30 |
37 | 31 | 30 | 35 |
19 | 24 | 40 | |
27 | |||
Fill in the missing data. (Round your p-value to 4
decimal places, mean values to 1 decimal place, and other answers
to 2 decimal places.)
Treatment | Mean | n | Std. Dev |
Physician 1 | |||
Physician 2 | |||
Physician 3 | |||
Physician 4 | |||
Total | |||
One-Factor ANOVA | |||||
Source | SS | df | MS | F | p-value |
Treatment | |||||
Error | |||||
Total | |||||
(a) Based on the given hypotheses, choose the correct
option.
H_{0}: μ_{1} = μ_{2}
= μ_{3} = μ_{4}
H_{1}: Not all the means are equal
α = 0.05
Reject the null hypothesis if F > 3.01
Reject the null hypothesis if F < 3.01
(b) Calculate the F for one factor.
(Round your answer to 2 decimal places.)
F for one factor is
Not attempted
(c) On the basis of the above findings, we reject the null
hypothesis. Is the statement true?
No
Yes
putting above data in excel: data-data analysis: ANOVA(one factor):
Mean | n | Std. Dev | |
Physician 1 | 27.6 | 7 | 6.75 |
Physician 2 | 32.8 | 6 | 4.02 |
Physician 3 | 27.9 | 8 | 5.06 |
Physician 4 | 32.4 | 7 | 4.65 |
Total | 30.0 | 28 | 5.54 |
Source | SS | df | MS | F | p-value |
Treatment | 166.86 | 3 | 55.62 | 2.01 | .1389 |
Error | 663.14 | 24 | 27.63 | ||
Total | 830.00 | 27 |
a)
Reject the null hypothesis if F > 3.01
b)
F for one factor is =2.01
c)
No (since test statistic is less than critical value)
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