Answer)
As the population standard deviation is unknown, we will use two sample t test
First we need to estimate the mean and s.d for both the groups.
Final:
u1 = 76
S1 = 21.436
For test 1
u2 = 67
S2 = 29.6648
N1 = n2 = 5
Test statistics (t) = (u1-u2)/standard error
Standard error = √{(s1^2/n1)+(s2^2/n2)}
After substitution
t = 0.5498645920498
Degrees of freedom is smaller of n1-1,n2-1
In this case df = 4
For df = 4 and test statistics = 0.5499
Required p-value is = 0.305856
As the obtained p-value is greater than the given significance level of 0.05
We fail to reject the null hypothesis
And we do not have enough evidence to support the claim that the scores have improved.
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