Question 2
Tossing a coin 15 times, let be the number of tails obtained.
(a) The mean of this binomial distribution is .
(b) The standard deviation (to the neatest tenth) of this binomial distribution is .
(c) The the probability of getting 6 heads is (round to the nearest thousandth).
(d) The probability of getting at least 2 tails is (round to 6 decimal places).
(e) The probability that the number of tails is between 5 and 10, exclusive, is (round to the nearest hundredth).
Let X be the number of tails obtained .
Then X~ Bin ( n = 15 , p = 0.5) assuming that the coin is unbiased .
a) Mean of binomial distribution is np . So, here mean is np = 7.5
b) Sd of binomial distribution is
c) P[ Getting 6 head ]
=P [ Getting 15-6= 9 tails ]
d) P[ Getting at least 2 tails ]
e)
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