A-. Consider the data set {1,2,4,5,7,8,9,9,10,1,12,11,14,16,17,20,22,23,25,27,35}
B-.GPAs at CCSU are normally distributed with a mean of 2.38 and a standard deviation of 0.45. Find the z-score for a GPA of 3.06. and discuss the significance of the z-score.
SolutionA:
use R software .boxplot function to get the boxplot.
Rcode;
sample <-
c(1,2,4,5,7,8,9,9,10,1,12,11,14,16,17,20,22,23,25,27,35)
boxplot(sample,main="boxplot", col = "pink")
fivenum(sample)
abline(h = min(sample), col = "Blue",horizontal = TRUE)
abline(h = max(sample), col = "Yellow")
abline(h = median(sample), col = "Green")
Output:
Fivenum summary from boxplot is
minimum value=1
first quartile=Q1=7
second quartile=Q2=11
third quartile=Q3=20
maximum value=35
B-.GPAs at CCSU are normally distributed with a mean of 2.38 and a standard deviation of 0.45.
Z score=x-mean/stddeviation
=3.06-2.38/0.45
=0.68/0.45
=1.511111
z score for GPA=3.06 is 1.511111
it means it lies 1.51111 standard deviations away from mean.
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