Question

Read eText and review Resource Materials.

Then post your solution to this problem: Given Hypothesis:

Ho: population mean μo = 200

Ha: population mean μo < 200 This is Left-Tailed test.

Population Standard Deviation σ = 50.

Given Significance Level is 0.10 (10%).

Critical z-value for 0.10 significance level and Left-Tailed test is (-1.28).

Rejection Region will be to the left of z= - 1.28. -3…………..-2………….-1…………0……….1

Choose your sample mean, x̅ (any integer between 180 and 195) and your sample size, n, ( any integer between 16 and 36). Perform the steps below and reach your conclusion: reject Ho or do not reject Ho.

Steps to follow: 1. Calculate your test statistics z-value: z = ( x̅- 200) / (50/√n) 2. Compare your z value with the critical value -1.28. 3. If your z-value is less than -1.28 (falls in Rejection Region) then reject Ho. If your z-value is greater than -1.28 (does not fall in Rejection Region) then do not reject Ho. Show all three steps; just the answer will not be graded.

Answer 1

SOLUTION:-

GIVEN THE FOLLOWING DATA

H0 :   = 200

Ha : < 200

= 0.10

critical z valve, z* = - 1.28

rejection region will be to the left of z= -1.28

population std dev , =50.0000

let Sample size ,n= 20

let Sample Mean, x̅ =185

1) Z- test statistic =( (x̅-) / (s/√n) =(185-200) / (50/√20) = -1.342

2) Z start < -1.28

3) reject Ho because Z- valve is less than -1.28 (falls in Rejection Region)

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