Question

1. An ANOVA was carried out on a set of data with 4 groups of 4...

1. An ANOVA was carried out on a set of data with 4 groups of 4 subjects each. The responses are presented in the following table:

Subject

A1

A2

A3

A4

S1

4

5

9

8

S2

5

5

10

8

S3

6

6

7

6

S4

5

4

6

6

  1. Complete the ANOVA table (52 pts)

Source

SS

df

MS

F

Factor A

__

__

_

___

Subject

__

__

___

Within/error

__

__

___

Total

__

___

  1. Find and report the critical value(s) and make a statistical decision for the F statistic and perform a post-hoc test, if applicable. (23 pts)

Homework Answers

Answer #1

using excel>data>data analysis >two way anova without replication

we have

Anova: Two-Factor Without Replication
SUMMARY Count Sum Average Variance
S1 4 26 6.5 5.666667
S2 4 28 7 6
S3 4 25 6.25 0.25
S4 4 21 5.25 0.916667
A1 4 20 5 0.666667
A2 4 20 5 0.666667
A3 4 32 8 3.333333
A4 4 28 7 1.333333
ANOVA
Source of Variation SS df MS F P-value F crit
Factor A 6.5 3 2.166667 1.695652 0.236872 3.862548
Subject 27 3 9
Error 11.5 9 1.277778
Total 45 15

the table is

Source of Variation SS df MS F P-value
Factor A 6.5 3 2.166667 1.695652 0.236872
Subject 27 3 9
Error 11.5 9 1.277778
Total 45 15

F = 1.69

critical value F(3,9) = 3.86

since F<3.86 so we do not reject Ho and so we cannot perform post hoc test

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The owner of a small business is considering three options: buying a computer, leasing a computer,...
The owner of a small business is considering three options: buying a computer, leasing a computer, or getting along without a computer. Based on the information obtained from the firm’s accountant, the following payoff table (in terms of net profit) was developed: State of Nature Alternative S1 S2 S3 A1 4 2 5 A2 8 2 3 A3 3 4 6 Based on the probability for each state of nature in previous question(the probability for S1 to happen is twice...
A linear regression analysis was carried out and from the sample data, the partially filled ANalysis...
A linear regression analysis was carried out and from the sample data, the partially filled ANalysis Of VAriance (ANOVA) given in part (a) was obtained. Based on it, answer the following: ========== a) Complete the ANalysis Of VAriance (ANOVA) table below. Source  Source df  df SS  SS MS  MS Regression (Model)  Regression (Model) 11 86.5986.59 19.930319.9303 Residual Error  Residual Error 2828    Total  Total 2929 208.24208.24       -------- b) The regression standard error, s=s=   -------- c) To test  H0:β1=0H0:β1=0 based on the given information,   the value of...
The following ANOVA table was obtained from a balanced completely randomized design: Source df SS MS...
The following ANOVA table was obtained from a balanced completely randomized design: Source df SS MS F Treatment 126 Error 20 16 Total 23 Fill in the blanks in this table. Determine the number of treatments. Determine the number of replications per treatment. Perform a statistical test to see if there is a difference between the true mean responses to the treatment.
1. For the question below, please do the following: a) State the null and alternative hypotheses....
1. For the question below, please do the following: a) State the null and alternative hypotheses. (3 pts) b) Fill in the ANOVA table (Show work to receive full credit. At minimum you must show the formula and what values are substituted in for each element of the formula along with your final answer. You many use Excel to obtain the sums and squared values.) (43 pts – 2 pts each except SS values are 5 pts each) c) Determine...
6. (36 pts) The following is an incomplete ANOVA summary table: Source df SS MS F...
6. (36 pts) The following is an incomplete ANOVA summary table: Source df SS MS F Among Groups 3 63 Within Groups 16 97 Total (a) Complete the ANOVA summary table. (b) Determine the number of groups. (b) At the α = 0.05 level of significance, determine whether there is evidence of difference in the population means.
Complete the ANOVA summary table below. In addition, answer the following questions for the ANOVA summary...
Complete the ANOVA summary table below. In addition, answer the following questions for the ANOVA summary table. a. What is the factorial notation? b. How many conditions were in the study? c. How many subjects were in the study? d. Identify significant main effects and interaction effects. Source   df SS MS F A 2 40 B 3 60 A x B 6 150 Error 72 Total 83 400
Instructions- Calculate this ANOVA by hand. Check your work by also calculating the ANOVA in SPSS...
Instructions- Calculate this ANOVA by hand. Check your work by also calculating the ANOVA in SPSS or EXCEL. Be sure to do any multiple comparison tests and interpret the results. Control GroupA1 PsychoanalysisA2 CBTA3 X1 7 7 3 X2 10 5 3 X3 6 6 2 X4 8 5 3 X5 10 5 4 X6 10 6 2 X barA1 SX (A1) SX2 SST = SX2 – T2/an                            (also called [X] – [T]) SST =                                                 (a =...
1. A one-factor ANOVA for independent samples conducted on 4 experimental groups, with n = 8...
1. A one-factor ANOVA for independent samples conducted on 4 experimental groups, with n = 8 participants in each group, produces the following partial outcomes: SSbetween = 36, SSwithin = 84. For this analysis, what is the computed F statistic? A. F = 3 B. F = 12 C. F = 8 D. F = 6 E. F = 21 F. F = 4 2. A researcher reports an outcome of one factor ANOVA for independent samples as F(2, 36)...
The owner of a small business is considering three options: buying a computer, leasing a computer,...
The owner of a small business is considering three options: buying a computer, leasing a computer, or getting along without a computer. Based on the information obtained from the firm’s accountant, the following payoff table (in terms of net profit) was developed: State of Nature Alternative S1 S2 S3 A1 4 2 5 A2 8 2 3 A3 3 4 6 Based on the probability for each state of nature in previous question(the probability for S1 to happen is twice...
Consider the partial ANOVA table shown below. Let a = .01 Source of Variation DF SS...
Consider the partial ANOVA table shown below. Let a = .01 Source of Variation DF SS MS F Between Treatments 3 180 Within Treatments (Error) Total 19 380 If all the samples have five observations each: there are 10 possible pairs of sample means. the only appropriate comparison test is the Tukey-Kramer. all of the absolute differences will likely exceed their corresponding critical values. there is no need for a comparison test – the null hypothesis is not rejected. 2...