Question

Determine the sample size n needed to construct a 90?% confidence interval to estimate the population mean when

? = 48 and the margin of error equals 8.

n =

Answer #1

Solution :

Given that,

standard deviation = = 48

margin of error = E = 8

At 90% confidence level the z is ,

= 1 - 90% = 1 - 0.90 = 0.10

/ 2 = 0.10 / 2 = 0.05

Z_{/2}
= Z_{0.05} = 1.645

Sample size = n = ((Z_{/2}
*
) / E)^{2}

= (1.645 * 48) / 8)^{2}

= 94.4169 = 94

Sample size = 94

Determine the margin of error for an 80% confidence interval to
estimate the population mean with sigmaequals51 for the following
sample sizes. a) n equals 35 b) n equals 41 c) n equals 60 Click
the icon to view the cumulative probabilities for the standard
normal distribution
. a) When nequals35, the margin of error for an 80%
confidence interval is____. (Round to two decimal places as
needed.)
b) When nequals41, the margin of error for an 80% confidence
interval...

Use the sample data and confidence level to construct the
confidence interval estimate of the population proportion p. n
equals 600 comma x equals 120 comma 90 % confidence nothingless
than p less than nothing (Round to three decimal places as
needed.)

Assuming that the population is normally distributed, construct
a 90 % confidence interval for the population mean, based on the
following sample size of n equals 6. 1, 2, 3, 4 comma 5, and 30
In the given data, replace the value 30 with 6 and recalculate the
confidence interval. Using these results, describe the effect of
an outlier (that is, an extreme value) on the confidence
interval, in general. Find a 90 % confidence interval for the
population mean,...

Assume that you want to construct a 95% confidence interval
estimate of a population mean. Find an estimate of the sample size
needed to obtain the specified margin of error for the 95%
confidence interval. The sample standard deviation is given
below.
Margin of errors=$6,
standard deviation=$22
The required sample size is __

Determine the margin of error for a confidence interval to
estimate the population proportion for the following confidence
levels with a sample proportion equal to 0.35 and n= 120
the margin of error for a confidence interval to estimate the
population portion for 90% confidence level is
the margin of error for a confidence interval to estimate the
population portion for 95% confidence level is
the margin of error for a confidence interval to estimate the
population portion for 97%...

Determine the margin of error for a confidence interval to
estimate the population mean with n=37 and σ=48 for the following
confidence levels.
a)
92 %
b)
94 %
c)
98 %

Determine the margin of error for a confidence interval to
estimate the population mean with n = 15 and s =15.8 for the
confidence levels below A. 80% B. 90% C. 99%

Construct a 90% confidence interval to estimate the population
mean using the accompanying data. What assumptions need to be made
to construct this interval?
x= 55 σ= 11 n=16
What assumptions need to be made to construct this
interval?
A. The sample size is less than 30.
B. The population must be normally distributed.
C. The population is skewed to one side.
D. The population mean will be in the confidence interval.

Construct a 90% confidence interval to estimate the population
proportion with a sample proportion equal to 0.50 and a sample size
equal to 150. What are the upper and lower limits?

Find the margin of error for a 95% confidence interval for
estimating the population mean when the sample standard deviation
equals 90 with a sample size of (i) 484 and (ii) 1600
(i) Find the margin of error for a 95% confidence interval for
estimating the population mean when the sample standard deviation
equals 90 with a sample size of 484
(ii).
(ii) Find the margin of error for a 95% confidence interval
for estimating the population mean when the...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 32 seconds ago

asked 3 minutes ago

asked 3 minutes ago

asked 4 minutes ago

asked 8 minutes ago

asked 8 minutes ago

asked 9 minutes ago

asked 10 minutes ago

asked 17 minutes ago

asked 22 minutes ago

asked 24 minutes ago

asked 24 minutes ago