5)
According to a university's reports,the GPAs of all of its students has a mean of 3.3 and standard deviation of 0.15. Females make up 59% of the entire student body.
If you were to take a large number of random samples of size n = 49 and record the sample mean GPA for each sample, the mean of these sample means would be approximately
Group of answer choices
0.15
0.59
0.070
49
3.3
0.021
6)
According to a university's reports,the GPAs of all of its students has a mean of 3.2 and standard deviation of 0.20. Females make up 56% of the entire student body.
If you were to take a large number of random samples of size n = 42 and record the sample mean GPA for each sample, the mean of these sample means would be approximately
Group of answer choices
42
0.031
0.2
0.56
0.077
3.2
7)
According to a university's reports,the GPAs of all of its students has a mean of 3.3 and standard deviation of 0.15. Females make up 59% of the entire student body.
If you were to take a large number of random samples of size n = 49 and record the proportion of females for each sample, the mean of these sample proportions would be approximately
Group of answer choices
0.59
49
0.070
0.15
0.021
3.3
8)
According to a university's reports,the GPAs of all of its students has a mean of 3.2 and standard deviation of 0.23. Females make up 41% of the entire student body.
If you were to take a large number of random samples of size n = 51 and record the proportion of females for each sample, the mean of these sample proportions would be approximately
Group of answer choices
0.069
51
0.23
3.2
0.032
0.41
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5) Answer 3.3
Reason : Large sample follows Normal distribution ( central limit theorem)
6) Answer 3.2
Reason: Large sample follows Normal distribution ( central limit theorem)
7) Answer 0.59
Reason: we expecting that sample contains 0.59 * 49 = 28.91 = 29 females .... sample proportion = 29/49 = 0.59183673
8) Answer 0.41
Reason: we expecting that sample contains 0.41 * 51= 20.91 = 21 females .... sample proportion = 21/51 = 0.41176471
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