According to an article in American Scientist, IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the following probabilities:
a) The probability that a randomly selected person has an IQ score of at least 111.
b) The probability that a randomly selected person has an IQ of less than 96.
c) The probability that a randomly selected person has an IQ score between 119 and 145.
(Please show all work.)
Solution:-
Mean = 100, S.D = 15
a) The probability that a randomly selected person has an IQ score of at least 111 is 0.232.
x = 111
By applying normal distruibution:-
z = 0.733
P(z > 0.7333) = 0.232.
b) The probability that a randomly selected person has an IQ of less than 96 is 0.605.
x = 96
By applying normal distruibution:-
z = - 0.267
P(z < - 0.267) = 0.605
c) The probability that a randomly selected person has an IQ score between 119 and 145 is 0.102.
x1 = 119
x2 = 145
By applying normal distruibution:-
z1 = 1.2667
z2 = 3.0
P( 1.2667 < z < 3.00) = P(z > 1.2667) - P(z > 3.0)
P( 1.2667 < z < 3.00) = 0.103 - 0.001
P( 1.2667 < z < 3.00) = 0.102
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