Question

construct a 90% confidence interval x=2544 n=3814

construct a 90% confidence interval
x=2544
n=3814

Homework Answers

Answer #1

Solution:

Confidence interval for Population Proportion is given as below:

Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)

Where, P is the sample proportion, Z is critical value, and n is sample size.

We are given

x = 2544

n = 3814

P = x/n = 2544/3814 = 0.667016256

Confidence level = 90%

Critical Z value = 1.6449

(by using z-table)

Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)

Confidence Interval = 0.667016256 ± 1.6449* sqrt(0.667016256*(1 – 0.667016256)/3814)

Confidence Interval = 0.667016256 ± 1.6449* 0.0076

Confidence Interval = 0.667016256 ± 0.0126

Lower limit = 0.667016256 - 0.0126 = 0.6545

Upper limit = 0.667016256 + 0.0126 = 0.6796

Confidence interval = (0.6545, 0.6796)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Construct a 90% confidence interval to estimate the population mean using the data below. x? =...
Construct a 90% confidence interval to estimate the population mean using the data below. x? = 90 ? = 10 n = 30 N = 300 The? 90% confidence interval for the population mean is? (_,_).
Construct a 90% and 95%confidence interval x=3956 n=14124 Find the width of both intervals
Construct a 90% and 95%confidence interval x=3956 n=14124 Find the width of both intervals
If n=13, (x-bar)=34, and s=4, construct a confidence interval at a 90% confidence level. Assume the...
If n=13, (x-bar)=34, and s=4, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. ____ < μμ < ____
Construct a confidence interval of the population proportion at the given level of confidence. x=160, n...
Construct a confidence interval of the population proportion at the given level of confidence. x=160, n =200, 90 % confidence The lower bound is ____. The upper bound is ____.
If n=30, ¯xx¯(x-bar)=49, and s=10, construct a confidence interval at a 90% confidence level. Assume the...
If n=30, ¯xx¯(x-bar)=49, and s=10, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. _______< ? < ________
Construct the confidence interval for the population mean μ. c=0.90​, x=16.1​, σ=8.0, and n=85 A 90%...
Construct the confidence interval for the population mean μ. c=0.90​, x=16.1​, σ=8.0, and n=85 A 90% confidence interval for μ is ( , ). ​(Round to one decimal place as​ needed.)
If n=32, ¯xx¯(x-bar)=36, and s=5, construct a confidence interval at a 90% confidence level. Assume the...
If n=32, ¯xx¯(x-bar)=36, and s=5, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. < μμ <
Construct a 90​% confidence interval of the population proportion using the given information. x=40, n=200 The...
Construct a 90​% confidence interval of the population proportion using the given information. x=40, n=200 The lower bound is? The upper bound is? (round to three decimal places as needed)
Construct a 90​% confidence interval of the population proportion using the given information. x=120, n=300 The...
Construct a 90​% confidence interval of the population proportion using the given information. x=120, n=300 The lower bound is____ The upper bound is_____ ​(Round to three decimal places as​ needed.)
Construct a 90​%confidence interval estimate for the population means given the values below. x=290 σ=67 n=279
Construct a 90​%confidence interval estimate for the population means given the values below. x=290 σ=67 n=279