A humanities professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below the top 13% and above the bottom 60% C: Scores below the top 40% and above the bottom 23% D: Scores below the top 77% and above the bottom 8% F: Bottom 8% of scores Scores on the test are normally distributed with a mean of 70 and a standard deviation of 9.6. Find the minimum score required for an A grade. Round your answer to the nearest whole number, if necessary.
Solution :
mean = = 70
standard deviation = =9.6
Using standard normal table,
a ) P(Z < z) = 13%
P(Z < z) = 0.13
P(Z < -1.126) = 0.13
z =-1.126
Using z-score formula,
x = z * +
x = -1.126 * 9.6 + 70
= 59.19
Minimum score = 59
b ) P(Z > z) = 40%
1 - P(Z < z) = 0.40
P(Z < z) = 1 - 0.40 = 0.60
P(Z < 0.2533) = 0.60
z = 0.2533
Using z-score formula,
x = z * +
x = 0.2533 * 9.6 + 70
= 72.43
Minimum score = 72
c ) P(Z < z) = 23%
P(Z < z) = 0.60
P(Z < -1.126) = 0.13
z =-1.126
Using z-score formula,
x = z * +
x = -1.126 * 9.6 + 70
= 59.19
Minimum score = 59
d ) P(Z > z) = 8%
P(Z < z) = 0.08
P(Z < -1.405) = 0.08
z = -1.405
Using z-score formula,
x = z * +
x = -1.405 * 9.6 + 70
= 56.51
Minimum score = 52
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