The following is a summary of data for 960 branch managers in the two major regions of a Canadian Bank:
Education Level |
Domestic Region |
International Region |
TOTAL |
No Degree |
120 |
20 |
140 |
Bachelor’s Degree |
420 |
100 |
520 |
Post-graduate Degree |
250 |
50 |
300 |
TOTAL |
790 |
170 |
960 |
1. State the null and alternative hypotheses for a Chi Square test to determine if managers’ education level is dependent of which region they are from.
2. State the rejection rule using the critical value approach. Let alpha = 0.05.
3. Calculate the expected frequency for the cell “No Degree” and “International Region”
4. If the Chi Square statistic is 2.176, what is your conclusion?
1)
Ho: managers’ education level is independent of which region they are from
H1: managers’ education level is dependent of which region they are from
2)
Level of Significance = 0.05
Number of Rows = 3
Number of Columns = 2
Degrees of Freedom=(#row - 1)(#column -1) = 2
Critical Value = 5.991 [
Excel function: =CHISQ.INV.RT(α,DF) ]
reject Ho, if test stat >5.991
3)
Expected frequency of a cell = sum of row*sum of column / total sum = 170*140/960 = 24.7917
4)
since, test stat=2.176< 5.991 , do not reject Ho
Conclusion: managers’ education level is independent of which region they are from
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