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According to a study, 78% of all ages 18-29 years had broadband internet access at random...

According to a study, 78% of all ages 18-29 years had broadband internet access at random home in 2011. A researcher wanted to estimate the proportion of undergraduates college student (18-23) with access, so she randomly sampled 184 undergraduates and found that 161 had access. Estimate the true proportion with 99%confidence.

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Answer #1

Given that, n = 184 and x = 161

=> sample proportion = 161/184 = 0.875

A 99% confidence level has significance level of 0.01 and critical value is,

The 99% confidence interval estimate for the true proportion is,

Therefore, required confidence interval is (0.8122, 0.9378)

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