A textile manufacturing process finds that on average, three
flaws occur per every 180 yards of material produced.
a. What is the probability of exactly one flaws in
a 180-yard piece of material? (Round your answer to 4
decimal places.)
b. What is the probability of no more than two flaws in a 180-yard piece of material? (Round your answer to 4 decimal places.)
c. What is the probability of no flaws in a 72-yard piece of material? (Round your answer to 4 decimal places.)
X ~ Poisson ( )
Where = 3 flaws per 180 yards.
Poisson probability distribution is
P(X) = e- * X / X!
a)
P(X = 1) = e-3 * 31
= 0.1494
b)
P( X <= 2) = P( X = 0) + P (X = 1) + P (X = 2)
= e-3 * 30 / 0! + e-3 * 31 / 1! + e-3 * 32 / 2!
= 0.4232
c)
For 72 yards, = 72/180 * 3 = 1.2
P( X = 0) = e-1.2 * 1.20
= 0.3012
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