Question

As part of a water quality​ survey, you test the water hardness in several randomly selected...

As part of a water quality​ survey, you test the water hardness in several randomly selected streams. The results are shown below. Construct a confidence interval for the population variance sigma squaredσ2 and the population standard deviation sigmaσ.Use a 95 % level of confidence. Assume that the population has a normal distribution.

nequals=23

sequals=16 grains per gallon

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The annual earnings of 13 randomly selected computer software engineers have a sample standard deviation of...
The annual earnings of 13 randomly selected computer software engineers have a sample standard deviation of $ 3660. Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance sigma squared and the population standard deviation sigma. Use a 90 % level of confidence. Interpret the results.
The diameters​ (in inches) of 17 randomly selected bolts produced by a machine are listed. Use...
The diameters​ (in inches) of 17 randomly selected bolts produced by a machine are listed. Use a 99​% level of confidence to construct a confidence interval for ​(a) the population variance sigma squared and ​(b) the population standard deviation sigma. Interpret the results. 4.477 4.427 4.024 4.309 4.006 3.742 3.829 3.749 4.224 3.961 4.128 4.573 3.958 3.742 3.857 3.832 4.465 ​ (a) The confidence interval for the population variance is ​(__,__​). ​(Round to three decimal places as​ needed.)
In a survey of randomly selected subjects, the mean age of 40 respondents is 36.4 years,...
In a survey of randomly selected subjects, the mean age of 40 respondents is 36.4 years, and the sample standard deviation of all ages is known to be 10.1 years. Construct a 95% confidence interval estimate of the mean age of the population from which the sample was selected.
Here are summary statistics for randomly selected weights of newborn​ girls: nequals=169169​, x overbarxequals=27.627.6 ​hg, sequals=6.96.9...
Here are summary statistics for randomly selected weights of newborn​ girls: nequals=169169​, x overbarxequals=27.627.6 ​hg, sequals=6.96.9 hg. Construct a confidence interval estimate of the mean. Use a 9090​% confidence level. Are these results very different from the confidence interval 26.526.5 hgless than<muμless than<28.928.9 hg with only 1616 sample​values, x overbarxequals=27.727.7 ​hg, and sequals=2.72.7 ​hg? What is the confidence interval for the population mean muμ​? nothing hgless than<muμless than<nothing hg ​(Round to one decimal place as​ needed.) Are the results between...
The annual earnings of 14 randomly selected computer software engineers have a sample standard deviation of...
The annual earnings of 14 randomly selected computer software engineers have a sample standard deviation of $3668. Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance sigma squared σ2 and the population standard deviation σ. Use a 95% level of confidence. Interpret the results. 1. What is the confidence interval for the population variance σ2​? (____,___) 2. Interpret the results. Select the correct choice below and fill in the answer​ box(es) to...
Here are summary statistics for randomly selected weights of newborn​ girls: nequals=181​, x overbarxequals=32.3 ​hg, sequals=6.8...
Here are summary statistics for randomly selected weights of newborn​ girls: nequals=181​, x overbarxequals=32.3 ​hg, sequals=6.8 hg. Construct a confidence interval estimate of the mean. Use a 98​% confidence level. Are these results very different from the confidence interval 30.9 hg less than <muμ less than<34.134.1 hg with only 17 sample​ values, x overbarxequals=32.5​hg, andsequals=2.5​hg?
Here are summary statistics for randomly selected weights of newborn​ girls: nequals 250​, x overbar equals27.5...
Here are summary statistics for randomly selected weights of newborn​ girls: nequals 250​, x overbar equals27.5 ​hg, s equals 7.1 hg. Construct a confidence interval estimate of the mean. Use a 95 ​% confidence level. Are these results very different from the confidence interval 26.6 hg less than muless than29.6 hg with only 17 sample​ values, x overbar equals 28.1 ​hg, and sequals 2.9 ​hg? What is the confidence interval for the population mean u ​? nothing hg less than...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.00 years and the standard deviation is 8.74 years. a) Construct a 95% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be 9.0 years?
The California Health Survey involved 51,048 randomly selected adults in California. The author selected 100 of...
The California Health Survey involved 51,048 randomly selected adults in California. The author selected 100 of those subjects and obtained these results. Among the 53 females, the mean height is 63.7 inches and the standard deviation is 4.5 inches. Among the 47 males, the mean is 69.2 inches and the standard deviation is 3.1 inches. The author selected subjects from the California Health Survey and 53 were female. Construct a 95% confidence interval for the percentage of adults Californians that...
A survey of 100 randomly selected Michigan residents finds that the they spend a mean of...
A survey of 100 randomly selected Michigan residents finds that the they spend a mean of $21 per month on going to the movies. An independent study of a 100 randomly selected California residents find that they spend a mean of $46 per month on going to the movies. Assume that the population standard deviation for the Michigan residents is $5 per month and that the population standard deviation for the California residents is $23 per month. Answer the following...