Question

Approximately 67.4% of patients are white. Approximately 43.2% of patients are female. Approximately 34.7% of patients are BOTH white AND female. Calculate the percentage of patients that are EITHER white OR female. Which probability rule did you use to answer this question? Show your work.

Answer #1

Probability that a patient is white : P(A) = 67.4/100 = 0.674

Probability that a patient is female : P(B) = 43.2/100 = 0.432

Probability that a patient is both white and female : P(A and B) = 34.7/100 = 0.347

By Addition theorem of probability,

P(A or B) = P(A) + P(B) - P(A and B)

Probability that a patient is EITHER white OR female = P(A or B) = 0.674+0.432-0.347 = 0.759

Percentage of patients that are EITHER white OR female = 0.759*100 = 75.9

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