A research group conducted an extensive survey of 2933 wage and
salaried workers on issues ranging from relationships with their
bosses to household chores. The data were gathered through
hour-long telephone interviews with a nationally representative
sample. In response to the question, "What does success mean to
you?" 1499 responded, "Personal satisfaction from doing a good
job." Let p be the population proportion of all wage and salaried
workers who would respond the same way to the stated
question.
Find a 90% confidence interval for p. (Round your answers to three
decimal places.)
lower limit ____
upper limit ___
Here total wage and salaried workers = 2933
Here total responded positive = 1499
sample proportion = p^ = 1499/2933 = 0.511
confidence interval = 90%
crtiical test statistic = 1.645
margin of error (MOE) = critical test statsitic * standard error of mean
standard error of mean = sqrt [p^ * (1-p^)/n] = sqrt [0.511 * (1 - 0.511)/2933]
= 0.015
90% confidence interval = p^ +- MOE = 0.511 +- 0.015
Lower Limit = 0.511- 0.015 = 0.496
Upper Limit = 0.511 + 0.015 = 0.526
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