Paint 1 |
Paint 2 |
Paint 3 |
Paint 4 |
120 |
120 |
117 |
128 |
112 |
130 |
122 |
131 |
121 |
121 |
123 |
131 |
118 |
126 |
115 |
129 |
118 |
126 |
123 |
127 |
121 |
114 |
126 |
126 |
118 |
117 |
126 |
137 |
Solution
We will perform One Way Anova to find the solution using Excel
So the output for One Way Anova is obtained using excel are given below
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
paint 1 | 7.0000 | 828.0000 | 118.2857 | 9.5714 | ||
paint 2 | 7.0000 | 854.0000 | 122.0000 | 31.6667 | ||
paint 3 | 7.0000 | 852.0000 | 121.7143 | 17.9048 | ||
paint 4 | 7.0000 | 909.0000 | 129.8571 | 13.4762 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 503.2500 | 3.0000 | 167.7500 | 9.2400 | 0.0003 | 4.7181 |
Within Groups | 435.7143 | 24.0000 | 18.1548 | |||
Total | 938.9643 | 27.0000 |
Write the Null and Alternative hypothesis to test whether there is a difference in dry time between the samples of each paint?
What statistic would you use to analyze this?
We will use F -statistic
F-statistic = 9.2400
At a 0.01 level of significance, what would be your decision rule
Since F-statistic = 9.2400 > F critical = 4.7181 so we reject the null hypothesis, at 0.01 level of significance.
From your analysis, is there a difference between drying times?
Since we are rejecting the null hypothesis so we have enough evidence to conclude that there is a difference between drying times.
If there was a difference in dry times how would you determine which paint has the different drying time?
F-statistic = 9.2400 > F critical = 4.7181
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