Using the information below construct 3 separate Pareto diagrams as follows:
Construct a Pareto chart for the different operator and machine combinations (without regard to individual defects)
Construct a Pareto chart for the five different days (without regard to defect)
Construct a Pareto chart for the type of defect.
What can you conclude from the 3 diagrams
Operator |
Machine |
Mon |
Tue |
Wed |
Thu |
Fri |
A |
1 |
@@@@ ** OO ## + |
@@@@@ * OOO # |
@@@@@ ***** OOOO ## + |
@@@@ * OOO ## |
@@@@@ * OOOO ### |
2 |
@@ * O |
@@@ ** OO * |
@@@ ***** OO # |
@@ * O # |
@@ ** O # |
|
B |
3 |
@@ ** |
@@@@ * |
@@@ ***** O # |
@@@ * O # + |
@@@@ * OO # |
4 |
@@ * OO + |
@@@ * O # |
@@@ **** OO # |
@@@ + # |
@@ + OO # |
|
@ = Strain * = Scratch O = Pinholes
# = Crack + = Other |
Note: Confirmed the data presented is accurate and does not need to be updated.
1. pareto chart for different operators and machines
operators | machine | monday | tuesday | wednesday | thursday | friday | total defects |
A | 1 | 11 | 10 | 17 | 10 | 13 | 61 |
A | 2 | 4 | 6 | 10 | 7 | 8 | 34 |
B | 3 | 4 | 8 | 11 | 5 | 6 | 35 |
B | 4 | 6 | 6 | 10 | 5 | 6 | 33 |
from the above table it shows as operator A machine 1 causes more defects
2 pareto data for days
days | defects |
monday | 25 |
tuesday |
30 |
wednesday | 48 |
thursday | 27 |
friday | 33 |
from the above table it shows that in wednesday more defects caused.
3. pareto data for different defects
defect name | number of defects |
strain | 64 |
strach | 38 |
pinholes | 34 |
crack | 20 |
other | 6 |
from the above table it shows that due to strain more defects caused
from the above three data table we conclude that we have to eradicate defects in Operator A Machine 1 Strain defect ion Wednesday which is cause for more defects,
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