Question

The proportion of adults who wear costumes to work on St. Patrick’s Day is claimed to...

The proportion of adults who wear costumes to work on St. Patrick’s Day is claimed to be greater than 0.12. 20 working adults are randomly selected from across the nation and 2 of them wore costumes to work on St. Patrick’s Day. Use ? = 0.05. Choose closest answer wherever necessary.

1.) Identify the definition of this test.

A. H0 : p > 0.12 H1 : p < 0.12

B. H0 : p ? 0.12 H1 : p > 0.88

C. H0 : p < 0.12 H1 : p > 0.88

D. H0 : p ? 0.12 H1 : p < 0.88

E. H0 : p ? 0.12 H1 : p > 0.12

2.) What is the test statistic (closest answer)?

A. -0.45

B. -2.12

C. 1.33

D. -0.3

E. 0.05

3.) What is the critical value for this test?

A. 2.44

B. 2.13

C. 1.64

D. 2.38

E. 2.18

4.)What is the p-value for this test?

A. 0.6172

B. 0.792

C. 0.2652

D. 0.183

E. 0.3443

5.)Identify the true statement about this test.

A. At a 95% confidence level we do not reject H1 as there is 38.28% probabilistic support toward the null hypothesis.

B. At a 5% confidence level we do not reject H0 as there is 38.28% probabilistic support toward the alternative hypothesis.

C. At a 95% confidence level we do not reject H0 as there is 38.28% probabilistic support toward the null hypothesis.

D. At a 95% confidence level we do not reject H0 as there is 38.28% probabilistic support toward the alternative hypothesis.

E. At a 5% confidence level we do not reject H0 as there is 61.72% probabilistic support toward the alternative hypothesis.

Homework Answers

Answer #1

n = 20

? = 0.05

p > 0.12

So, the hypothesis will be -

1)

H0 : p ? 0.12

H1 : p > 0.12

Because we need to verify the claim if p is greater than 0.12 and so because there is a > it cannot come in the Null Hypothesis

That will be option (E)

2)

? = sqrt[ P * ( 1 - P ) / n ] = sqrt(0.12*0.88/20) = 0.073

p1 = 2/20 = 0.1

Test statistic, Z = (p1-p)/? = (0.1-0.12)/0.073 = -0.274

That will be option (D)

3) Critical value= Z at 95% CI for one-sided test = 1.65

That will be option (C)

4) p-value:P(Z<-0.274) + P(Z>-0.274) = 2*0.3916 = 0.792

So, that will be (B)

5) p>?  

So, at 95% confidence, we do not reject H0 as there is 38.28% probabilistic support toward the null hypothesis

So, that will be option (C)

Let me know if you need anything else, if not please don't forget to like the answer :)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
13. Test the claim that the proportion of men who own cats is larger than 18%...
13. Test the claim that the proportion of men who own cats is larger than 18% at the .005 significance level. The null and alternative hypothesis would be: A) H0:μ=0.18   H1:μ<0.18 B) H0:μ=0.18   H1:μ>0.18 C) H0:μ=0.18   H1:μ≠0.18 D) H0:p=0.18   H1:p≠0.18 E) H0:p=0.18   H1:p<0.18 F) H0:p=0.18 H1:p>0.18 The test is: left-tailed   two-tailed   right-tailed Based on a sample of 50 people, 16%16  owned cats The p-value is: _______(to 2 decimals) Based on this we: A) Reject the null hypothesis B) Fail to reject...
Test the claim that the proportion of men who own cats is significantly different than 70%...
Test the claim that the proportion of men who own cats is significantly different than 70% at the 0.2 significance level. The null and alternative hypothesis would be: A) H0:μ=0.7H0:μ=0.7 H1:μ>0.7H1:μ>0.7 B) H0:μ=0.7H0:μ=0.7 H1:μ≠0.7H1:μ≠0.7 C) H0:μ=0.7H0:μ=0.7 H1:μ<0.7H1:μ<0.7 D) H0:p=0.7H0:p=0.7 H1:p>0.7H1:p>0.7 E) H0:p=0.7H0:p=0.7 H1:p<0.7H1:p<0.7 F) H0:p=0.7H0:p=0.7 H1:p≠0.7H1:p≠0.7 The test is: A) right-tailed B) two-tailed C) left-tailed Based on a sample of 35 people, 66% owned cats The test statistic is: ____ (to 2 decimals) The positive critical value is:____ (to 2...
1) Test the claim that the proportion of men who own cats is significantly different than...
1) Test the claim that the proportion of men who own cats is significantly different than 70% at the 0.1 significance level. a) The null and alternative hypothesis would be: H0:p=0.7 7H1:p<0.7 H0:μ=0.7 H1:μ>0.7 H0:p=0.7 H1:p>0.7 H0:μ=0.7 H1:μ≠0.7 H0:μ=0.7 H1:μ<0.7 H0:p=0.7 H1:p≠0.7 b)The test is: 2) Based on a sample of 70 people, 78% owned cats a) The test statistic is: ______ (to 2 decimals) b) The positive critical value is: ________ (to 2 decimals) c) Based on this we:...
1) Test the claim that the proportion of people who own cats is smaller than 80%...
1) Test the claim that the proportion of people who own cats is smaller than 80% at the 0.01 significance level. a) The null and alternative hypothesis would be: H0:p=0.8 H1:p≠0.8 H0:μ=0.8 H1:μ≠0.8 H0:μ≤0.8 H1:μ>0.8 H0:p≥0.8 H1:p<0.8 H0:μ≥0.8 H1:μ<0.8 H0:p≤0.8 H1:p>0.8 b) The test is: 2) Based on a sample of 500 people, 75% owned cats a) The test statistic is: ________ (to 2 decimals) b) The p-value is: _________ (to 2 decimals) 3) Based on this we: Reject the...
Test the claim that the proportion of men who own cats is larger than 23% at...
Test the claim that the proportion of men who own cats is larger than 23% at the .025 significance level. The null and alternative hypothesis would be: a. H0:μ=0.23H0:μ=0.23 H1:μ>0.23H1:μ>0.23 b. H0:p=0.23H0:p=0.23 H1:p≠0.23H1:p≠0.23 c. H0:μ=0.23H0:μ=0.23 H1:μ≠0.23H1:μ≠0.23 d. H0:p=0.23H0:p=0.23 H1:p>0.23H1:p>0.23 e.H0:μ=0.23H0:μ=0.23 H1:μ<0.23H1:μ<0.23 f. H0:p=0.23H0:p=0.23 H1:p<0.23H1:p<0.23 The test is: a. right-tailed b. two-tailed c. left-tailed Based on a sample of 50 people, 16%16%  owned cats The p-value is:  (to 2 decimals) Based on this we: a. Reject the null hypothesis b. Fail to reject...
Test the claim that the proportion of men who own cats is smaller than the proportion...
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .01 significance level. The null and alternative hypothesis would be: H0:μM=μF H1:μM≠μF H0:pM=pF H1:pM>pF H0:μM=μF H1:μM<μF H0:μM=μF H1:μM>μF H0:pM=pF H1:pM<pF H0:pM=pF H1:pM≠pF The test is: left-tailed two-tailed right-tailed Based on a sample of 60 men, 40% owned cats Based on a sample of 40 women, 50% owned cats The test statistic is:  (to 2 decimals) The p-value is:  (to...
Test the claim that the proportion of men who own cats is smaller than the proportion...
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level. The null and alternative hypothesis would be: H0:?M=?F H1:?M??F H0:pM=pF H1:pM?F H0:pM=pF H1:pM?pF H0:pM=pF H1:pM>pF H0:?M=?F H1:?M<?F The test is: two-tailed left-tailed right-tailed Based on a sample of 80 men, 45% owned cats Based on a sample of 80 women, 65% owned cats The test statistic is: (to 2 decimals) The p-value is: (to...
3.3 Q: A supplier of digital memory cards claims that a proportion of less than 20%...
3.3 Q: A supplier of digital memory cards claims that a proportion of less than 20% of the cards are defective. In a random sample of 145 memory cards, it is found that 6 are defective. At the 5% level of significance, use the given sample to test the manufacturer’s claim that less than 20% of the items are defective. Identify the null hypothesis and alternative hypothesis, test statistic, P -value, conclusion about the null hypothesis, and final conclusion that...
Test the claim that the proportion of people who own cats is smaller than 70% at...
Test the claim that the proportion of people who own cats is smaller than 70% at the 0.10 significance level. The null and alternative hypothesis would be: H0:μ=0.7H0:μ=0.7 H1:μ≠0.7H1:μ≠0.7 H0:p≤0.7H0:p≤0.7 H1:p>0.7H1:p>0.7 H0:p≥0.7H0:p≥0.7 H1:p<0.7H1:p<0.7 H0:μ≤0.7H0:μ≤0.7 H1:μ>0.7H1:μ>0.7 H0:p=0.7H0:p=0.7 H1:p≠0.7H1:p≠0.7 H0:μ≥0.7H0:μ≥0.7 H1:μ<0.7H1:μ<0.7 The test is: left-tailed two-tailed right-tailed Based on a sample of 300 people, 65% owned cats The test statistic is:  (to 2 decimals) The p-value is:  (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is larger than 50% at...
Test the claim that the proportion of men who own cats is larger than 50% at the .025 significance level. The null and alternative hypothesis would be: H0:μ=0.5H0:μ=0.5 H1:μ>0.5H1:μ>0.5 H0:p=0.5H0:p=0.5 H1:p>0.5H1:p>0.5 H0:μ=0.5H0:μ=0.5 H1:μ≠0.5H1:μ≠0.5 H0:p=0.5H0:p=0.5 H1:p≠0.5H1:p≠0.5 H0:p=0.5H0:p=0.5 H1:p<0.5H1:p<0.5 H0:μ=0.5H0:μ=0.5 H1:μ<0.5H1:μ<0.5 The test is: two-tailed left-tailed right-tailed Based on a sample of 65 people, 51% owned cats The test statistic is:  (to 2 decimals) The critical value is:  (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT