Question

1.Spring break can be a very expensive holiday. A sample of 95 students is surveyed, and...

1.Spring break can be a very expensive holiday. A sample of 95 students is surveyed, and the average amount spent by students on travel and beverages is $593.84. The sample standard deviation is approximately $369.34. a.) Construct a 90% confidence interval for the population mean amount of money spent by spring breakers.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider a sample of 30 college students from Victoria. Based on this sample, it was found...
Consider a sample of 30 college students from Victoria. Based on this sample, it was found that the average amount spent on beverages during the Halloween weeekend was $40. The population standard deviation is $6.50. Assume the following: the population of college students is very large relative to the sample size, and the population is normally distributed. What is the upper confidence limit for an 88% confidence interval around the population mean? Express your solution rounded to two decimal places.
1.      A questionnaire of spending habits was given to a random sample of college students. Each...
1.      A questionnaire of spending habits was given to a random sample of college students. Each student was asked to record and report the amount of money they spent on books and school supplies in a semester. The amount of money spent on books and school supplies is said to follow normal distribution. The sample of 85 students resulted in an average of $850.   a)     What are the simple conditions necessary for the confidence interval to be valid? b)     Find...
1. The 95% confidence interval states that 95% of the sample means of a specified sample...
1. The 95% confidence interval states that 95% of the sample means of a specified sample size selected from a population will lie within plus and minus 1.96 standard deviations of the hypothesized population mean. T or F 2. Which of the following is NOT necessary to determine how large a sample to select from a population? Multiple Choice The level of confidence in estimating the population parameter The size of the population The maximum allowable error in estimating the...
Construct a 95% confidence interval for the population mean. A sample of 34 college students had...
Construct a 95% confidence interval for the population mean. A sample of 34 college students had mean annual earnings of $4520 with a standard deviation of $677
1. A random sample of 429 college students was interviewed about a number of matters. For...
1. A random sample of 429 college students was interviewed about a number of matters. For each of the below, write a sentence summarizing the results (i.e “I am 95% confident that….”) a. They reported that they had spent an average of $378.23 on textbooks during the previous semester. If the sample standard deviation for these data is $15.78, construct an estimate of the population mean at the 95% confidence level. b. They also reported that they had visited the...
A random sample of 25 college students attending the RWU Spring Concert showed that they had...
A random sample of 25 college students attending the RWU Spring Concert showed that they had an average amount of $15.00 cash in their pockets. This same sample data had a sample standard deviation of $2.50. a. (3 pts.) What is the point estimate for the population mean µ, amount of cash in the pockets of a RWU student? b. (4 pts.) Find the 95% confidence interval for the population mean µ, amount of cash in the pockets of a...
Question 1 A random sample of 49 teenagers from a large population was surveyed, and the...
Question 1 A random sample of 49 teenagers from a large population was surveyed, and the average number of movies that they had rented in the past week was x = 1.9, with a sample standard deviation of s = 0.5. a) Construct a 95% confidence interval for the average number of movies rented by teenagers in a week . b) Construct a 99% confidence interval for the average number of movies rented by teenagers in a week.
a recent study of 25 students showed they spent average of $18.53 on gas per week,...
a recent study of 25 students showed they spent average of $18.53 on gas per week, the sample standard deviation of the sample was $3.00, construct a 95% confidence interval for the mean amount spent on gas per week
A random sample of 90 UT business students revealed that on average they spent 8 hours...
A random sample of 90 UT business students revealed that on average they spent 8 hours per week on Facebook. The population standard deviation is assumed to be 2 hours per week. If we want to develop a 95% confidence interval for the average time spent per week on Facebook by all UT business students, the margin of error of this interval is The 95% confidence interval for the average time spent per week on Facebook by all UT business...
In a random sample of 47 high-school students enrolled in SAT test training, it was determined...
In a random sample of 47 high-school students enrolled in SAT test training, it was determined that the mean amount of money spent per student was $110.96 per class with a sample standard deviation of $8.30. Construct and interpret a 95% confidence interval for the population mean amount spent per student for an SAT class. A) ($108.52, $113.40); We are 95% confident that the population mean amount spent per student for a single SAT class is between $108.52 and $113.40....