*More than 2 dependent samples*
Andrzejewski, Spencer, Kelley, and Berridge trained 8 rats in a signal detection procedure. That is, the rats had to respond on two levers (left or right) signifying whether they had just seen a tiny green light or not. Prior to test sessions, each of the rats was given a drug injection. The dependent variable was the percentage of trials in which they responded correctly.
Drug |
|||||
Rat |
Saline |
mg/kg Amphetamine |
0.25 mg/kg Amphetamine |
0.5 mg/kg Ritalin |
1.0mg/kg Ritalin |
1 |
84% |
84% |
84% |
88% |
88% |
2 |
90% |
90% |
90% |
88% |
91% |
3 |
84% |
83% |
94% |
89% |
89% |
4 |
92% |
92% |
87% |
94% |
90% |
5 |
92% |
93% |
97% |
96% |
92% |
6 |
88% |
78% |
88% |
90% |
93% |
7 |
88% |
88% |
94% |
94% |
94% |
8 |
80% |
82% |
87% |
83% |
82% |
The researchers hypothesized that since amphetamine and Ritalin are used therapeutically to improve attention in humans, it might improve signal detection in rats. What would you conclude?
We can answer this using a paired t test as the same rats were used in a below and after setup
We enter the data in excel and then goto data > data analysis tab and select t test paired
lets perform the analysis for one variable and the same procedure can be applied to the remaining 3 variables as well
Hypothesis
H0 : signal detection is not improved due to 0.25mg/kp
amphetamine
H1 : signal detection is significantly improved due to 0.25mg/kp
amphetamine
we set the signficance level = 0.05
so we reject the null hypothesis if the p value of the 1 tail test is less than 0.05
as the p value is 0.07 , which is not less than 0.05 , hence we fail to reject the null hypothesis
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